-0.15x^2+1.08x+5.4=0

Solution for -0.15x^2+1.08x+5.4=0 equation:

-0.15x^2+1.08x+5.4=0

a = -0.15; b = 1.08; c = +5.4;
Δ = b2-4ac
Δ = 1.082-4·(-0.15)·5.4
Δ = 4.4064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.08)-\sqrt{4.4064}}{2*-0.15}=\frac{-1.08-\sqrt{4.4064}}{-0.3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.08)+\sqrt{4.4064}}{2*-0.15}=\frac{-1.08+\sqrt{4.4064}}{-0.3}
$